(t^2+4t)*(2t+4)=1

Solution for (t^2+4t)*(2t+4)=1 equation:

Simplifying
(t2 + 4t)(2t + 4) = 1

Reorder the terms:
(4t + t2)(2t + 4) = 1

Reorder the terms:
(4t + t2)(4 + 2t) = 1

Multiply (4t + t2) * (4 + 2t)
(4t * (4 + 2t) + t2(4 + 2t)) = 1
((4 * 4t + 2t * 4t) + t2(4 + 2t)) = 1
((16t + 8t2) + t2(4 + 2t)) = 1
(16t + 8t2 + (4 * t2 + 2t * t2)) = 1
(16t + 8t2 + (4t2 + 2t3)) = 1

Combine like terms: 8t2 + 4t2 = 12t2
(16t + 12t2 + 2t3) = 1

Solving
16t + 12t2 + 2t3 = 1

Solving for variable 't'.

Reorder the terms:
-1 + 16t + 12t2 + 2t3 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 16t + 12t2 + 2t3 = 0

The solution to this equation could not be determined.